Assertion (A) : If $\mathrm{x}+\frac{{\mathrm{x}}^2}{2}+\frac{{\mathrm{x}}^3}{3}+\dots \dots \infty =\log \left(\frac{7}{6}\right) \mathrm{then} \mathrm{x}=\frac{1}{7}$

Reason(R) : If $\left|\mathrm{x}\right|<1, \mathrm{then} \mathrm{x}+\frac{{\mathrm{x}}^2}{2}+\frac{{\mathrm{x}}^3}{3}+\dots \dots \infty =\log \left(\frac{1}{1-\mathrm{x}}\right)$

A is true, R is true and R is correct explanation of A

A is true, R is true and R is not correct explanation of A

A is true, R is false

A is false, R is true