Assertion (A): Acetamide on reaction with KOH and bromine gives acetic acid.

Reason (R): Bromine catalyses hydrolysis of acetamide

Reaction between acetamide and $\mathrm{NaOH}/{\mathrm{Br}}_2$,

${\mathrm{CH}}_3{\mathrm{CONH}}_2+4\mathrm{KOH}+{\mathrm{Br}}_2\to {\mathrm{CH}}_3{\mathrm{NH}}_2+{\mathrm{Na}}_2{\mathrm{CO}}_3+2\mathrm{KBr}+2{\mathrm{H}}_2\mathrm{O}$

So, the final product is methylamine, not acetic acid.

And, the role of bromine is to react with anion to form N-bromoamide.

Thus, both the assertion and the reason are false.

Hence, option (D) is correct.