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Assertion (A): Aniline cannot be prepared by Gabriel phthalimide synthesis.
Reason (R): $- N H_{2}$ group in aniline is highly activating towards electrophilic substitution.

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Both A and R are false

A is true but R is false

Both A and R true, and R is correct explanation of A

Both A and R are true but R is not the correct explanation of A

answer is B.

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$C_{6} H_{5} C l$ is non reactive towards nucleophilic substitution

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