Assertion (A): If Rolle’s theorem be applied in $f\left(x\right)$ , then L.M.V. theorem is also applicable for  $f\left(x\right)$.
Reason (R): Both Rolle’s theorem & L.M.V. theorem can not be applied in   $f\left(x\right)=\left|\sin \left|x\right|\right| \text{in }\left[-\frac{\pi }{3},\frac{\pi }{3}\right].$
The codes are given below, select the correct codes.
 

For Rolle’s theorem & L.M.V theorem, the function $f\left(x\right)$ must be continuous & differentiable in the interval $(a,b)$  if Rolle’s theorem is applicable for $f\left(x\right)$  then L.M.V. theorem is applicable for  $f\left(x\right)$ $\because f\left(x\right)=\left|\sin \left|x\right|\right|\text{in}\left[\frac{-\pi }{3},\frac{\pi }{3}\right].$
is  non differentiable at   $x=0$
Rolle’s theorem $\&$ L.M.V theorem can not be applicable 
for  $f\left(x\right)=\left|\sin \left|x\right|\right|\forall x\in \left[\frac{-\pi }{3},\frac{\pi }{3}\right].$