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Assertion (A): The value of e lies between 2 and 3.
Reason (R) : $e = 1 + \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \dots$

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A is false, R is true

A is true, R is true and R is correct explanation of A

A is true, R is false

A is true, R is true and R is not correct explanation of A

answer is A.

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Detailed Solution

$\begin{array}{rcl} e & = & 2 \cdot 718 \\ 2 & < & e < 3 \\ and e & = & 1 + \frac{1}{1} + \frac{1}{2} + \frac{1}{3} + \dots \dots \end{array}$

(A) is true

(B) is true

(R) is correct explanation of (A)

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