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Assertion (A): Though the central atom of both $N H_{3} a n d H_{2} O$ molecules are $s p^{3}$ hybridized, yet H–N–H bond angle is greater than that of H–O–H.
Reason (R): $N H_{3}$ has lone pair-bond pair repulsions which are more than bond pair-bond pair repulsions where as $H_{2} O$ has lone pair-lone pair repulsions which are more than lone pair-bond pair and bond pair-bond pair repulsions

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A and R both are false.

A is true but R is false

A and R both are correct, but R is not the correct explanation of A.

A and R both are correct, and R is the correct explanation of A.

answer is A.

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Detailed Solution

Repulsions order $L P - L P > L P - B P > B P - B P$

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