Assertion: In simple harmonic motion, the velocity is maximum when acceleration is minimum
Reason: Displacement and velocity of SHM. differ is phase by $\frac{π}{2}$ .

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If both statement I and statement II are true and statement II is the correct explanation of statement I.

If both statement I and statement II are true but statement II is not the correct explanation of statement I.

If statement I is true but statement II is false

If both statement I and statement II are false

answer is B.

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Detailed Solution

$x = a \sin ωt and v = \frac{dx}{dt} = aω \cos ωt$

phase difference between ‘x’ and ‘a’ is $\frac{π}{2}$ .

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