Assertion: Minimum distance between object and its real image by a convex lens is $4 f$ .
Reason: If object distance from a convex lens is $2 f$ , then its image distance is also $2 f$ .

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If Assertion is false but the Reason is true.

If both Assertion and Reason are true and the Reason is not the correct explanation of the Assertion.

If Assertion is true, but the Reason is false.

If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

answer is A, B.

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Detailed Solution

If D be the distance between the object and the real image , then v = D - u

Therefore , $\frac{1}{(D - u)} - \frac{1}{(- u)} = \frac{1}{+ f} \Rightarrow u^{2} - D u + D f = 0$

For all real values of u , ${(- D)}^{2} - 4 D f \geq 0 \Rightarrow D_{m i n} = 4 f$ ( Here object distance u must be greater than f )

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