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Q.

Assertion(A): Approximate value of (1.0002)3000 is 1.6

Reason(R): For the differentiable function f(x+δx)≈f(x)+f1(x)⋅δx where δx is change in x. 

The correct answer is

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a

A, R are true R⇏A

b

A is true R is false

c

A is false R is true

d

A, R are true and R⇒A

answer is A.

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Detailed Solution

f(x)=x3000,x=1,δx=0.0002

⇒f(x+δx)≃f(x)+f1(x)δ

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Assertion(A): Approximate value of (1.0002)3000 is 1.6Reason(R): For the differentiable function f(x+δx)≈f(x)+f1(x)⋅δx where δx is change in x. The correct answer is