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Q.

Assertion (A) : 3+i6+3-i6=-128 Reason (R) : If n is a positive integer then 3+in+3-in=2n+1Cos6

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a

Both A and R are true R is correct  explanation A

b

Both A and R are true but R is not correct  explanation to A

c

A is true R is false

d

A is false R is true

answer is A.

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Detailed Solution

(A)

  3+i6+3-i6 =2632+i2+2632-i26 =26cosπ6+i sinπ66+cosπ6-i sinπ66 =26cosπ+i sinπ+cosπ-i sinπ =26(2cosπ) =27(-1)=-27=-128

(R)

  3+in+3-in =2ncosπ6+i sinπ6n+cosπ6-i sinπ6n =2ncos nπ6+i sin nπ6+cos nπ6-i sin nπ6 =2n2cos nπ6=2n+1 cos nπ6

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