Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Assume that a tunnel is dug across the earth passing through its center. Find the time taken by the particle to reach other end, when it is projected in to dug with a speed of $\sqrt{gR}$ is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

\frac{π}{2} \sqrt{\frac{R}{g}}

2 π \sqrt{\frac{R}{g}}

\frac{π}{\sqrt{2}} \sqrt{\frac{R}{g}}

π \sqrt{\frac{R}{g}}

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

y = A \sin ω t

Question Image

Where $y = R \Rightarrow υ = ω \sqrt{A^{2} - y^{2}}$

$\sqrt{gR} = ω \sqrt{A^{2} - R^{2}}$

$gR = ω^{2} (A^{2} - R^{2})$

$\Rightarrow A = \sqrt{2} R$

Phase difference between P & Q $= \frac{π}{2}$

Time difference between P & Q $= \frac{T}{4}$

$∴ t_{PQ} = \frac{T}{4} = \frac{T}{4} 2 π \sqrt{\frac{R}{g}}$

$∴ t_{PQ} = \frac{π}{2} \sqrt{\frac{R}{g}}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE