Assume that the acceleration due to gravity on the surface of the moon is 0.2 times the acceleration due to gravity on the surface of the earth. If $R_{e}$ is the maximum range of a projectile on the earth’s surface then what is the maximum range on the surface of the moon for the same velocity of projection

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0 {.2R}_{e}

{2R}_{e}

0 {.5R}_{e}

{5R}_{e}

answer is D.

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Detailed Solution

R = \frac{u^{2} \sin 2 θ}{g}

$\frac{R_{e}}{R_{m}} = \frac{0.2 g_{e}}{g_{e}}$

$R_{m} = \frac{R_{e}}{0.2} = \frac{10 R_{e}}{2} = 5 R_{e}$

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