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Q.

Assume that the reaction of MeMgBr  with ethylacetate proceeds with 100% conversion to give tert-butanol. The volume of 0.2 M solution of MeMgBr required to convert 10 mL of a 0.025 M solution of ethyl acetate to tert-butanol is ___mL. (Round off to one decimal place)

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answer is 2.5.

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Detailed Solution

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1 mol of ethylacetate react with 2 mol of MeMgBr 
Millimoles of ethylacetate = 10×0.025 = 0.25 millimoles. So for complete reaction.
MeMgBr  must be 0.50 millimoles
Volume of 0.2 M MeMgBr  containing 0.50 millimoles would be 0.2×V = 0.5
V=52mL V=2.5 mL

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