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Assuming 100% ionization, the increasing order of the freezing point of the solution will be

a
0.10 mol kg-1 Ba3PO42<0.10 mol kg-1Na2SO4<0.10 mol kg-1KCl
b
0.10 mol kg-1KCl<0.10 mol kg-1Na2SO4<0.10 mol kg-1Ba3PO42
c
0.10 mol kg-1Na2SO4<0.10 mol kg1Ba3PO42<0.10 mol kg1KCl
d
0.10 mol kg-1KCl<0.10 mol kg-1Ba3PO42<0.10 mol kg-1Na2SO4

detailed solution

Correct option is A

Assuming complete dissociation -ΔTfBa3PO42>-ΔTfNa2SO4>-ΔTfKCl

Hence TfBa3PO42<TfNa2SO4<TfKCl

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