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Assuming 2s-2p mixing is NOT operative, the paramagnetic species among the following is

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N₂

C₂

${Be}_{2}$

B₂

answer is C.

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Detailed Solution

1. Be₂: valence electrons =4

(σ2s)²(σ^∗2s)²

2. B₂: valence electrons =6

(σ2s)²(σ^∗2s)²(σ2p_z)²

3.C₂: valence electrons =8

(σ2s)₂(σ^∗2s)²(σ2p_z)²(π2p_x)¹(π2p_y)¹

4. N₂: valence electrons=10

(σ2s)²(σ^∗2s)²(σ2p_z)²(π2p_x)²(π2p_y)²

C2 has two unpaired electrons, thus its paramagnetic.

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