Assuming complete dissociation, which of the following aqueous solutions will have the same pH value.

$\text{ M.eq. of }0.01\mathrm{MHCl}=\frac{0.01\times 100}{1000}=1\times {10}^{-3}$ $pH=3$

$$\begin{gathered} \text{ M.eq. of }0.02\mathrm{MH}2\mathrm{SO}4=\frac{0.04\times 50}{1000}=2\times {10}^3 \\ 0.02\mathrm{MNaOH}=\frac{{\displaystyle 0.02\times 50}}{{\displaystyle 1000}}=1\times {10}^{-3} \\ \begin{array}{l}\text{ Left }\left[H^{+}\right]=2\times {10}^{-3}-1\times {10}^{-3}=1\times {10}^{-3}\\ pH=3\end{array} \end{gathered}$$