Assuming complete ionization, the pH of 0.1M HCl is 1.  The molarity of  $H_{2}S{O}_4$ with the same pH is  

$\left[H^{+}\right]$ in 0.1M HCl = 0.1M
For same pH,  $\left[H^{+}\right]in{H}_{2}S{O}_4=0.1M$
One mole $H_{2}S{O}_4\to 2H^{+}+S{O}_4^{2-}$
$\therefore 0.1M\left[H^{+}\right]$ will be given by
$=\frac{0.1}{2}=0.05M{H}_{2}S{O}_4$