Assuming human pupil to have a radius of 0.25cm and a comfortable viewing distance of 25 cm, the minimum seperation between two objects that human eye can resolve at 500 nm wavelength is

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$1\mu m\$

$30\mu m\$

$100\mu m\$

$300\mu m\$

answer is B.

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Detailed Solution

$\frac{{1.22\lambda }}{a} = \frac{d}{D}\,\,\,;\,\,\frac{{1.22 \times 500 \times {{10}^{ - 9}}}}{{2 \times 0.25 \times {{10}^{ - 9}}}} = \frac{d}{{25 \times {{10}^2}}}\$

$d = 30.5 \times {10^{ - 6}}m = 30\mu m\$

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