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Assuming Hund's Rule is not necessarily followed for a d⁵ configuration then what could be the maximum and minimum multiplicity possible?

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6,2

6,1

$\frac{5}{2}$ , $\frac{1}{2}$

5,1

answer is A.

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Detailed Solution

Multiplicity $= 2 | s | + 1$ , where s is the total electronic spin.

The maximum number of unpaired electrons that can fit in each orbital can be used to compute maximal multiplicity. and the smallest number of unpaired electrons that can fit into each orbital can be used to compute the minimal multiplicity.

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