Assuming pure 2s and 2p orbitals of carbon are used in forming CH₄ molecule, which of the following statement is false?

In the unhybridized state of carbon,2p orbitals are 90° to one another and each one will overlap with 1s orbital of three hydrogen atoms, thus three C-H bonds are formed which are 90° to one another. For the fourth hydrogen atom, its 1s orbital may overlap with non-directional 2s orbital of the carbon and this $\sigma$-bond will be stronger than $\sigma$C-H bonds formed by 2p-ls overlap. In such situation CH₄ molecule can never has tetrahedral geometry.