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Q.

Assuming the energy released per fission on  U235 is 200 MeV, the energy released in the fission of 1kg of  U235 is

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a

0.91×1013J

b

0.91×1011J

c

8.19×1011J

d

8.19×1013J

answer is D.

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Detailed Solution

E=200MeV=200×106×1.6×1019=3.2×1011

 Number of atom in 1kg uranium
 n=mNAm=1000×6.023×1023235
=2.56×1024
Total energy released
nE=2.56×1024×3.2×1011 =8.19×1013J

 

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Assuming the energy released per fission on  U235 is 200 MeV, the energy released in the fission of 1kg of  U235 is