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Q.

Assuming there no 2s – 2p mixing, the number of paramagnetic species amongst the following:
$H_{2}, {He}_{2}^{+}, {Li}_{2}, {Be}_{2}, B_{2}, C_{2}, C_{2}^{2 -}, N_{2}^{+}, N_{2}, O_{2}, O_{2}^{-}, S_{2} and F_{2}$ are _____________________

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answer is 6.

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Detailed Solution

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With no 2s – 2p mixing the order of energy of MO’s would be

$\begin{array}{l} σ_{1 s} < σ_{1 s}^{*} < σ_{2 s} σ_{2 s}^{*} < σ_{2 p z} < |π_{2 P_{x}} = π_{2 P_{y}}| < |π_{2 p_{y}}^{*} = π_{2 p_{x}}^{*}| < σ_{2 p_{2}} \\ H_{2} (D), H e_{2}^{+} (P), L i_{2} (D), B e_{2} (D), C_{2} (P), C_{2}^{2 -} (D), N_{2}^{+} (P), N_{2} O_{2} (P), O_{2}^{-} (P), S_{2} (P), F_{2} (D) . \end{array}$

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Assuming there no 2s – 2p mixing, the number of paramagnetic species amongst the following:H2,He2+,Li2,Be2,B2,C2,C22−,N2+,N2,O2,O2−,S2 and F2 are _____________________