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Q.

At 400C , the vapour pressure in torr of methanol and ethanol solution is P=119x+135  where x is the mole fraction of methanol. Hence, correct statement is/are

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a

vapour pressure of pure methanol is 119 torr

b

vapour pressure of pure ethanol is 135 torr

c

vapour pressure of equimolar mixture of each is  127 torr

d

mixture is completely immiscible

answer is B.

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Detailed Solution

detailed_solution_thumbnail

Total vapor pressure of the methanol and ethanol mixture:

P=119x+135...(1)

Expression is: 

P=PA0xA+PB0(1xA)

PA°=vapour pressure of pure methanol xA=mole fraction of methanol PB°=vapour pressure of pure ethanol

P=PA0xA+PB0PB0xA

P=PB0+(PA0PB0)xA...(2)

Equating (1) and (2):

PB0=135   ;PA0PB0=119

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