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Q.

At 0.821 atm and at 177° C, gas ${SO}_{3}$ occupies 45 L. 3 .Moles of neutrons present in ${SO}_{3}$ are : (Take NA= 6 x 10 23 )

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a

$24 \times 10^{24}$

b

$24 \times 10^{23}$

c

$6 \times 10^{24}$

d

40

answer is A.

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Detailed Solution

$n = \frac{0.821 \times 45}{0.0821 \times 450} = 1$ $O n e S O_{3}$ molecule contains 40 neutrons $∴ 1$ mole of $S O_{3}$ contains 40 mole neutrons..

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