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At 100⁰C the vapour pressure of a solution of 6.5 gm of a solute in 100 gm of water is 732 mm. If K_b = 0.52, the boiling point of this solution will be

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102^oC

103^oC

101^oC

100⁰C

answer is C.

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Detailed Solution

At 100^oc

P_{H_2O}^o=760mm(1atm)\\P_{sol.}=732mm\\W_{solute}=6.5g\\W_{H_2O}=100g

GMW of H₂O=18g

K_b(H₂O)= 0.52KKgmole^-1

(I) Assuming the solution is very dilute

\frac{P^o-P_s}{P^o}X\frac{1000}{GMW\;of\;solvent}=molality

m=2.05m

(II)

T_b(solution)-100=1.06

T_b(solution) = 101.06⁰C

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