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Q.

At 100°C and 1 atm, if the density of liquid water is 1.0g cm^-3 and that of water vapour is 0.0006gcm^-3, then the volume occupied by water molecules in one litre of steam at that temperature is:

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a

6cm³

b

0.6cm³

c

0.06cm³

d

60cm³

answer is C.

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Detailed Solution

Mass of 1 litre water vapour
$= V \times d = 1000 \times 0 .0006 = 0 .6 g$
$∴$ Volume of liquid water= $\frac{m}{d} = \frac{0 .6}{1} = 0 .6 {cm}^{3}$

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