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Q.

At 100°C and 1 atm, if the density of liquid water is 1.0g cm-3  and that of water vapour is 0.0006gcm-3, then the volume occupied by water molecules in one litre of steam at that temperature is:

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a

6cm3

b

60cm3

c

0.6cm3

d

0.06cm3

answer is C.

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Detailed Solution

Mass of 1 litre water vapour
=V×d=1000×0.0006=0.6g
∴Volume of liquid water= md=0.61=0.6cm3

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