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At $25^{\circ} C$ , the vapour pressure of pure liquid A (MW = 40) is 100 torr, while that of pure liquid B (MW = 80) is 40 torr. The vapour pressure at $25^{\circ} C$ of a solution containing 20 g of each of A and B is

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68 torr

80 torr

59.8 torr

48 torr

answer is A.

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Detailed Solution

$P = P_{A}^{0} X_{A} + P_{B}^{0} X_{B} = 100 \times \frac{2}{3} + 40 \times \frac{1}{3} = 80 t o r r$

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