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Q.

At 25oC the enthalpy of the following processes are given:
H2(g)+O2(g)2OH(g)ΔH=78kJmol1H2(g)+12O2(g)H2O(g)ΔH=2.42kJmol1H2(g)2H(g)ΔH=436kJmol112O2(g)O(g)ΔH=249kJmol1
What would be the value of X for the following reaction? ________________
(Nearest integer)
H2O(g)H(g)+OH(g)ΔH=XkJmol1

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answer is 499.

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Detailed Solution

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H2OH2+12O2    ΔH=24212H2+12O2OH    ΔH=3912H2H    ΔH=218H2OH+OH    ΔH=499

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