At 27°C the average speed of N₂ molecules is ms^-1. At 927° the speed will be ______ xms^-1

$$\begin{gathered} {\mathrm{T}}_1 =27+273 =300\mathrm{K} \\ {\mathrm{T}}_2 =927+273 =1200\mathrm{K} \\ {\mathrm{\mu }}_{\mathrm{avg}} =\sqrt{\frac{8\mathrm{RT}}{\mathrm{\pi M}}} \end{gathered}$$

$$\begin{gathered} \frac{{\mathrm{\mu }}_{927{}^0\mathrm{C}}}{{\mathrm{\mu }}_{27{}^0\mathrm{C}}}=\frac{\sqrt{1200K}}{\sqrt{300K}} \\ {\mathrm{\mu }}_{927{}^0\mathrm{C}}=2\times {\mathrm{\mu }}_{27{}^0\mathrm{C}} \\ =2\mathrm{x} ({\mathrm{\mu }}_{27{}^0\mathrm{C}}=\mathrm{x}) \end{gathered}$$