At 298 K, 1 atm, among

$2{\mathrm{H}}_{2\left(\mathrm{g}\right)}+{\mathrm{O}}_{2\left(\mathrm{g}\right)}\to 2{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{l}\right)}$

${\mathrm{H}}_{2\left(\mathrm{g}\right)}+{\mathrm{Cl}}_{2\left(\mathrm{g}\right)}\to 2{\mathrm{HCl}}_{\left(\mathrm{g}\right)}$

$N_{2\left(\mathrm{g}\right)}+{\mathrm{O}}_{2\left(\mathrm{g}\right)}\to 2{\mathrm{NO}}_{\left(\mathrm{g}\right)}$

${\mathrm{H}}_2{\mathrm{SO}}_{4\left(\mathrm{aq}\right)}+{\mathrm{KOH}}_{\left(\mathrm{aq}\right)}\to {\mathrm{K}}_2{\mathrm{SO}}_{4\left(\mathrm{s}\right)}+{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{l}\right)}$products, correct order of reaction rates is

D is neutralization reaction so very fast in ‘C’ ${\mathrm{N}}_2$ having triple bond and ${\mathrm{O}}_2$ having double. So bond breaking energy more it is slow reaction

In ‘A’${\mathrm{O}}_2$ having double bond but in B ${\mathrm{Cl}}_2$ having single bond. So bond breaking energy is less. So B is faster than A D>B>A>C