Q.

At 298 K, a 1 litre solution containing 10m mol of Cr2O72- and 100m mol Cr3+ shows a pH of 3.0.
Given: Cr2O72+ → Cr3+; E0 = 1.330V and 2.303RTF = 0.059 V
The potential for the half cell reaction is x×10-3V. The value of x  is___ 

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answer is 917.

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Detailed Solution

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Cr2O72+14H++6e2Cr+3+7H2OEH.cell =E00.0596logCr+32Cr2O72H+14=1.330.0596log(0.1)2(0.01)10314
= 0.917 V
= 9.17 x 10-3 V

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