Q.

At 298K, the equilibrium constant is 2×10-1 for the reaction: Cu(s)+2Ag+(aq)   Cu2+(aq)+2Ag(s)
 The equilibrium constant for the reaction

12Cu(aq)2++Ag(s)12Cu(s)+Ag(aq)+

is x×10-8. The value of x is ______.(Nearest Integer)

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answer is 2.

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Detailed Solution

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 Cu(s)+2Ag+(aq)  Cu2+(aq)+2Ag(s) Kc=2×101512Cu2+(aq)+Ag(s)=12Cu(s)+Ag+(aq)  Kc=1Kc1/2Kc=12×10151/2=5×10161/2=2.24×108The value of 'x' is 2. 

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