At 300 K, 3.2 grams of naphthalene is dissolved in CCl₄ to make a 250 ml solution. Osmotic pressure of the solution is (no association or dissociation of solute occurs in the solution)

$$\begin{gathered} \mathrm{\pi }=\mathrm{iCRT} ; \\ \mathrm{i}=1 \\ \mathrm{\pi }=1\times \frac{{\mathrm{w}}_{\mathrm{solute}}}{\mathrm{GMW} \mathrm{of} \mathrm{solute}}\times \frac{1000}{{\mathrm{V}}_{\mathrm{solution}} ( \mathrm{in} \mathrm{ml} )}\times \mathrm{RT} \\ \mathrm{Molar} \mathrm{mass} \mathrm{of} \mathrm{naphthalene}, {\mathrm{C}}_{10}{\mathrm{H}}_8=128 \mathrm{g}/\mathrm{mole} \\ \mathrm{\pi }=\frac{3.2 \mathrm{g}}{128 \mathrm{g}.{\mathrm{mol}}^{-1}}\times \frac{1000}{250 }\times 0.0821 \mathrm{lit}-\mathrm{atm}.{\mathrm{mol}}^{-1} {\mathrm{K}}^{-1}\times 300 \mathrm{K} \\ \mathrm{\pi }=2.463 \mathrm{atmospheres} ; \end{gathered}$$