At 300 K 40 ml of O3 dissolves in 100 g of water at 1 atm. What mass of O3 dissolved in 400 g of water at a pressure of 4 atm at 300 K.

m∝P(40×4)4mlO3dissolve in 400 gr water at 300 K and 4 atm.nO3 dissolved=4×640×10−30.0821×300=0.1mass of O3 = 4.5 gr

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At 300 K 40 ml of O₃ dissolves in 100 g of water at 1 atm. What mass of O₃ dissolved in 400 g of water at a pressure of 4 atm at 300 K.

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answer is 4.5.

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Detailed Solution

$m \propto P (40 \times 4) 4 {mlO}_{3}$ dissolve in 400 gr water at 300 K and 4 atm.
${nO}_{3} dissolved = \frac{4 \times 640 \times 10^{- 3}}{0 .0821 \times 300} = 0 .1$
mass of O₃ = 4.5 gr

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