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At 300 K and 2 bar,the density of a certain gaseous molecule is double to that of dinitrogen $(N_{2})$ at 300 K and 4 bar.The molar mass of gaseous molecule is

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$28 g {mol}^{- 1}$

$56 g {mol}^{- 1}$

$112 g {mol}^{- 1}$

$14 g {mol}^{- 1}$

answer is C.

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Detailed Solution

$\frac{P_{1} M_{1}}{P_{2} M_{2}} = \frac{d_{1}}{d_{2}} \frac{2 \times M_{1}}{4 \times 28} = \frac{2}{1} M_{1} = 112 g / mol$

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