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At 300k, 36gm of glucose present per litre in its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of solution is 1.52 bar at the same temperature, what would be its concentration?

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a

11grL^–1

b

22grL^–1

c

36grL^–1

d

42grL^–1

answer is A.

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Detailed Solution

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$Osmotic pressure, π = CRT At constant Temprature, π \propto C \frac{π_{1}}{π_{2}} = \frac{C_{1}}{C_{2}}; where, C = n / V C_{1} = concentration of glucose = \frac{36 / 180}{1} = \frac{36}{180} = 0.2 \frac{4.98}{1.52} = \frac{0.2}{C_{2}} C_{2} = 0.061 moles / lit = 0.061 \times 180 = 10.98 g / lit . \approx 11 g / lit .$

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At 300k, 36gm of glucose present per litre in its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of solution is 1.52 bar at the same temperature, what would be its concentration?