At 300K, the osmotic pressue of 300mL of a protein aqueous solution is 8.3 × 10–5 bar. The molar mass of protein is 104gmol–1. What is the weight (in g) of the protein present in this solution ?(R = 0.083 L bar mol–1 K–1)

π=CRT 8.3 ×10-5=C = 0.0831×300 on solving C= 13×10-5 C= molesVolume moles =10-6 moles= massmolar mass mass =10-6 × 10-4=0.01g

At 300K, the osmotic pressue of 300mL of a protein aqueous solution is 8.3 × 10–5 bar. The molar mass of protein is 104gmol–1. What is the weight (in g) of the protein present in this solution ?(R = 0.083 L bar mol–1 K–1)

π=CRT 8.3 ×10-5=C = 0.0831×300 on solving C= 13×10-5 C= molesVolume moles =10-6 moles= massmolar mass mass =10-6 × 10-4=0.01g

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At 300K, the osmotic pressue of 300mL of a protein aqueous solution is 8.3 × 10^–5 bar. The molar mass of protein is 10⁴gmol^–1. What is the weight (in g) of the protein present in this solution ?
(R = 0.083 L bar mol–1 K^–1)

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$π = CRT 8.3 \times 10^{- 5} = C = 0.0831 \times 300 on solving C = \frac{1}{3} \times 10^{- 5} C = \frac{moles}{Volume} moles = 10^{- 6} moles = \frac{mass}{molar mass} mass = 10^{- 6} \times 10^{- 4} = 0.01 g$

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At 300K, the osmotic pressue of 300mL of a protein aqueous solution is 8.3 × 10–5 bar. The molar mass of protein is 104gmol–1. What is the weight (in g) of the protein present in this solution ?(R = 0.083 L bar mol–1 K–1)

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At 300K, the osmotic pressue of 300mL of a protein aqueous solution is 8.3 × 10^–5 bar. The molar mass of protein is 10⁴gmol^–1. What is the weight (in g) of the protein present in this solution ?
(R = 0.083 L bar mol–1 K^–1)