At 363K, the vapour pressure of A is 21 kPa and that of B is 18kPa. One mole of A and 2 moles of B are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is _____ kPa.
(Round off to the Nearest integer).

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answer is 19.

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Detailed Solution

$X_{A} = \frac{1}{1 + 2} = \frac{1}{3}$
$X_{B} = 1 - \frac{1}{3} = \frac{2}{3}$
$P_{A}^{0} = 21 kPa, P {}_{B}= 18 kPa$
$P_{total} = P_{A}^{o} + P_{B}^{o}$
$= 21 \times 1 / 3 + 18 \times 2 / 3$
=7+12
=19 kPa

Hence, the correct answer 19 kPa

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