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Q.

At 375K and at a total pressure of one atmosphere sulphuryl chloride $({SO}_{2}, Cl)$ undergoes dissociation according to the equation : ${SO}_{2} {Cl}_{2} (g) ⇄ {SO}_{2} (g) + {Cl}_{2} (g)$ to the extent of 90%. Hence the work done in the process at the same temperature:

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a

$- 4.95 kJ$

b

$- 2.8 kJ$

c

$+ 53.6 kJ$

d

$- 1.4 kJ$

answer is B.

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Detailed Solution

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$PV = nRT dω = Pdν = \frac{- 1 \times R \times 375}{1} = - 3.117 KJ 90 % of 3.117 K J = - 2.8 KJ$

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At 375K and at a total pressure of one atmosphere sulphuryl chloride SO2,Cl undergoes dissociation according to the equation : SO2Cl2(g)⇄SO2(g)+Cl2(g) to the extent of 90%. Hence the work done in the process at the same temperature: