At 444°C , the equilibrium constant K for the reaction 2AB⇌A2+B2 is 164, The degree of dissociation of AB will be

2AB⇌A2+B21 0 01-2x a aKC=a2164=a2a=18=0.2a×100=20%

At 444°C , the equilibrium constant K for the reaction 2AB⇌A2+B2 is 164, The degree of dissociation of AB will be

2AB⇌A2+B21 0 01-2x a aKC=a2164=a2a=18=0.2a×100=20%

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At 444°C , the equilibrium constant K for the reaction $2 AB ⇌ A_{2} + B_{2} is \frac{1}{64},$ The degree of dissociation of AB will be

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Detailed Solution

$2 AB ⇌ A_{2} + B_{2}$

1 0 0

1-2x a a

$K_{C} = a^{2}$

$\frac{1}{64} = a^{2}$

$a = \frac{1}{8} = 0.2$

$a \times 100 = 20 %$

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At 444°C , the equilibrium constant K for the reaction 2AB⇌A2+B2 is 164, The degree of dissociation of AB will be

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At 444°C , the equilibrium constant K for the reaction $2 AB ⇌ A_{2} + B_{2} is \frac{1}{64},$ The degree of dissociation of AB will be