At 623K and at 10 atm K_p for N₂+3H₂$\rightleftharpoons$2NH₃ is 7 x 10^-4. At a certain instant,the partial pressures of N₂,H₂ and NH₃ in the reaction mixture are respectively 2.5 atm,3 atm and 4.5 atm respectively. Correct statement at equilibrium is that

Q_p = $\frac{{\mathrm{p}}_{{\mathrm{NH}}_3}^2}{{\mathrm{p}}_{{\mathrm{N}}_2}\times {\mathrm{p}}_{{\mathrm{H}}_2}^3}$=$\frac{{(4.5 \mathrm{atm})}^2}{2.5 \mathrm{atm}\times {(3 \mathrm{atm})}^3}$= 0.3 atm^-2 

Q_p > K_p reaction must move to left to reach equilibrium. At equilibrium partial pressures of N₂ and H₂ must be higher and partial pressure of NH₃ must be lower than the given values.