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At 760 torr pressure and 20°C temperature, 1 L of water dissolves 0.04 gm of pure oxygen or 0.02 gm of pure nitrogen. Assuming that dry air is composed of 20%oxygen and 80% nitrogen (by volume), the masses (in g/L) of oxygen and nitrogen dissolved by I L of water at 20°C exposed to air at a total pressure of 760 torr are respectively:

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0.04, 0.02

0.16,0.08

0.016,0.008

0.008,0.016

answer is A.

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Detailed Solution

Mass of oxygen $= \frac{20}{100} \times 0.04 = 0.008 g / L$
Mass of nitrogen $= \frac{80}{100} \times 0.02 = 0.016 g / L$

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