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Q.

At a certain place, the horizontal component of earth's magnetic field is $\sqrt{3}$ times the vertical component. The angle of dip at that place is

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a

$90^{0}$

b

$45^{0}$

c

$60^{0}$

d

$30^{0}$

answer is A.

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Detailed Solution

$B_{H} = \sqrt{3} B_{V},$ also $\tan θ = \frac{B_{V}}{B_{H}} = \frac{1}{\sqrt{3}} \Rightarrow θ = 30^{o}$

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