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Q.

At a certain depth “d” below surface of earth, value of acceleration due to gravity becomes four times that of its value at a height 3R above earth surface. Where R is Radius of earth (Take R=6400 km). The depth d is equal to

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a

5260km

b

2560 km

c

4800km

d

640km

answer is D.

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Detailed Solution

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We know,

Acceleration due to gravity at a depth d is 

gd= g1-dR

And acceleration due to gravity at a height h is 

gh=g1+hR-2

Given in the question 

gd=4×gh=3R

g1dR=4g1+3RR2

1-dR = 14d = 3R4

d = 4800km

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