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At a certain distance from a point charge the electric field is 500 V/m and the potential is 3000 V. What is this distance

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36 m

112 m

6 m

12 m

answer is A.

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Detailed Solution

$V = E \times r \Rightarrow r = \frac{V}{E} = \frac{3000}{500} = 6 m$

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