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At a certain temperature the RMS speeds of the molecules of two gases ‘x’ and ‘y’ have the ratio 3 : 1; the ratio of their molar masses M_x : M_y will be

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1 : 3

1 : 9

3 : 1

9 : 1

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{C_{x}}{C_{y}} = \sqrt{\frac{M_{y}}{M_{x}}} or \frac{M_{y}}{M_{x}} = \frac{3^{2}}{1^{2}} = \frac{9}{1} \\ ∴ \frac{M_{x}}{M_{y}} = 1 : 9 \end{array}$

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