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Q.

At a constant temperature a gas is initially at 2 atm pressure. To compress it to 1/8th of its initial volume, pressure to be applied is

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a

16atm

b

4atm

c

8atm

d

12atm

answer is D.

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Detailed Solution

$P_{1} = 2 atm$

$V_{1} = V$

$P_{2} = ?$

$V_{2} = V / 8$

$P_{1} V_{1} = P_{2} V_{2}$

$p_{2} = \frac{P 1 V_{1}}{V_{2}}$

$= \frac{2 \times V}{V / 8} = 16 atm$

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