At a given condition, 1 mole of  ${\text{O}}_{\text{2}}$ occupies 30 L, what is volume of occupied by 2.5 moles of  ${\text{O}}_{\text{2}}$

Molar of mass ${\text{O}}_{\text{2}}$ (=1mol) = 32 g
Equivalent mass ${\text{O}}_{\text{2}}$  = 8 g
Hence,   1 mol of  ${\text{O}}_{\text{2}}$ = 4 equivalent  ${\text{O}}_{\text{2}}$
If,  1 mol   ${\text{O}}_{\text{2}}$ occupies =30 ml
Then, 1 equivalent ${\text{O}}_{\text{2}}$ occupies =  $\frac{30}{4}$=7.5