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Q.

At a given instant the current and self-induced emf in an inductor are directed as indicated in figure.The induced emf is $25 V$ and the rate of change of the current is $25 k A / s;$ The inductance of the coil is L .Then

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a

$L = 1 m H$

b

L= $2 m H$

c

Current in the inductor is increasing

d

Current in the inductor is decreasing

answer is A, D.

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Detailed Solution

We have $e = L \frac{d i}{d t}$

$∴$ $L = \frac{e}{(d i / d t)} = \frac{25}{25 \times 10^{3}} = 1 \times 10^{- 3} H$

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