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Q.

At a given point of time the value of displacement of a simple harmonic oscillator is given as y =A cos(30°). If amplitude is 40cm and kinetic energy at that time is 200J, the value of force constant is 1.0 x 10x Nm-1. The value of x is _____.

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answer is 4.

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Detailed Solution

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E=U+K.E 
12KA2=12KY2+K.E
K=2(K.E)A2−Y2=2(K.E)A2−A2cos230

     =8(K.E)A2
=8×200(40×10−2)2=104

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